Message Board
| Message Board > Fenix / Bennu / Gemix / DIV > Process priority (fenix) |
| August 3, 2008, 14:41 | |
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OScoder
None 1338 posts |
Hi there, Just a quick question: is there a way to change the priority of a process, so that it is always the first one executed? Thanks, OScoder ____________ om |
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| August 3, 2008, 15:29 | |
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Htbaa
Perl 368 posts 
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In DIV2 you could do this inside a process. priority = 10 So if you have process t1() and t2() where t2() has it's priority set to 4 and t1() has it's priority set to 7 then t2() will be executed first. ____________ blog.htbaa.com |
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| August 3, 2008, 16:12 | |
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Rincewind
programmer 1558 posts 
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What Htbaa said is also correct for Fenix and Bennu. Priority is a local variable with default value zero.
____________ Personal website: http://www.loijson.com |
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| August 4, 2008, 13:29 | |
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Dennis
どこかにいる 2099 posts 
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if the priority is zero how will the compiler choose? (pick the first one it finds in his stack or something?)
____________ Kwakkel |
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| August 4, 2008, 15:03 | |
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Sandman
F3n!x0r 1196 posts 
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Actually t1() will be executed first, because it has a higher priority ( 7 > 4 ) than t2(). If priorities are equal, it's not defined. It's just the one that's next in the list. ____________ BennuWiki Yes, my avatar has grey borders in IE (so get a decent browser) ROOFLEZ ROOFLEZ |
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| August 4, 2008, 18:12 | |
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Htbaa
Perl 368 posts
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Oh well, I didn't check how it sorts the list. But thanks for making it clear :-)
____________ blog.htbaa.com |
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Message Board > Fenix / Bennu / Gemix / DIV > Process priority (fenix)